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sqrt(2x+1)=4 equation

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Numerical solution:

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The solution

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  _________    
\/ 2*x + 1  = 4
$$\sqrt{2 x + 1} = 4$$
Detail solution
Given the equation
$$\sqrt{2 x + 1} = 4$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{2 x + 1}\right)^{2} = 4^{2}$$
or
$$2 x + 1 = 16$$
Move free summands (without x)
from left part to right part, we given:
$$2 x = 15$$
Divide both parts of the equation by 2
x = 15 / (2)

We get the answer: x = 15/2

The final answer:
$$x_{1} = \frac{15}{2}$$
The graph
Rapid solution [src]
x1 = 15/2
$$x_{1} = \frac{15}{2}$$
x1 = 15/2
Sum and product of roots [src]
sum
15/2
$$\frac{15}{2}$$
=
15/2
$$\frac{15}{2}$$
product
15/2
$$\frac{15}{2}$$
=
15/2
$$\frac{15}{2}$$
15/2
Numerical answer [src]
x1 = 7.5
x1 = 7.5