Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation cos(x)=-2
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Equation (x-5)^2=(x+10)^2
-
Equation 2-3*(2*x+2)=5-4*x
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Equation x^4=(4x-21)^2
- Express {x} in terms of y where:
- -10*x+16*y=-6
- 2*x+2*y=-6
- -17*x+13*y=-3
- -11*x-14*y=-3
-
Identical expressions
- sqrt(1 zero x)- nine =0
- square root of (10x) minus 9 equally 0
- square root of (1 zero x) minus nine equally 0
- √(10x)-9=0
- sqrt10x-9=0
- sqrt(10x)-9=O
-
Similar expressions
- sqrt(10x)+9=0
sqrt(10x)-9=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$\sqrt{10 x} - 9 = 0$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{10 x + 0}\right)^{2} = 9^{2}$$
or
$$10 x = 81$$
Divide both parts of the equation by 10
We get the answer: x = 81/10
The final answer:
$$x_{1} = \frac{81}{10}$$
$$\sqrt{10 x} - 9 = 0$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{10 x + 0}\right)^{2} = 9^{2}$$
or
$$10 x = 81$$
Divide both parts of the equation by 10
x = 81 / (10)
We get the answer: x = 81/10
The final answer:
$$x_{1} = \frac{81}{10}$$
Sum and product of roots
[src]
sum
81
0 + --
10
$$0 + \frac{81}{10}$$
=
81 -- 10
$$\frac{81}{10}$$
product
81 1*-- 10
$$1 \cdot \frac{81}{10}$$
=
81 -- 10
$$\frac{81}{10}$$
81/10
The graph