7-sqrt(3-x)=4 equation
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The solution
Detail solution
Given the equation
$$7 - \sqrt{3 - x} = 4$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{3 - x}\right)^{2} = 3^{2}$$
or
$$3 - x = 9$$
Move free summands (without x)
from left part to right part, we given:
$$- x = 6$$
Divide both parts of the equation by -1
x = 6 / (-1)
We get the answer: x = -6
The final answer:
$$x_{1} = -6$$
Sum and product of roots
[src]
$$-6$$
$$-6$$
$$-6$$
$$-6$$