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7(2x-3)+19=4(x-8)

7(2x-3)+19=4(x-8) equation

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Numerical solution:

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The solution

You have entered [src]
7*(2*x - 3) + 19 = 4*(x - 8)
$$7 \left(2 x - 3\right) + 19 = 4 \left(x - 8\right)$$
Detail solution
Given the linear equation:
7*(2*x-3)+19 = 4*(x-8)

Expand brackets in the left part
7*2*x-7*3+19 = 4*(x-8)

Expand brackets in the right part
7*2*x-7*3+19 = 4*x-4*8

Looking for similar summands in the left part:
-2 + 14*x = 4*x-4*8

Move free summands (without x)
from left part to right part, we given:
$$14 x = 4 x - 30$$
Move the summands with the unknown x
from the right part to the left part:
$$10 x = -30$$
Divide both parts of the equation by 10
x = -30 / (10)

We get the answer: x = -3
The graph
Rapid solution [src]
x1 = -3
$$x_{1} = -3$$
x1 = -3
Sum and product of roots [src]
sum
-3
$$-3$$
=
-3
$$-3$$
product
-3
$$-3$$
=
-3
$$-3$$
-3
Numerical answer [src]
x1 = -3.0
x1 = -3.0
The graph
7(2x-3)+19=4(x-8) equation