Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 5x-3=2x
-
Equation 7-6x=-4x-6
-
Equation -40*(-7*x+5)=-1600
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Equation 7x+x+3=19
- Express {x} in terms of y where:
- 5*x-16*y=-20
- 6*x-3*y=15
- 10*x-14*y=9
- -11*x-16*y=-19
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Identical expressions
- one . five (x- three)= two . five (x- four)
- 1.5(x minus 3) equally 2.5(x minus 4)
- one . five (x minus three) equally two . five (x minus four)
- 1.5x-3=2.5x-4
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Similar expressions
- x^2+1.5*x-36=0
- 1.5(x+3)=2.5(x-4)
- 4(1.5x-3)-5.5x=10
- 1.5(x-3)=2.5(x+4)
1.5(x-3)=2.5(x-4) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
3*(x - 3) 5*(x - 4)
--------- = ---------
2 2
$$\frac{3 \left(x - 3\right)}{2} = \frac{5 \left(x - 4\right)}{2}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$\frac{3 x}{2} = \frac{5 x}{2} - \frac{11}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = - \frac{11}{2}$$
Divide both parts of the equation by -1
We get the answer: x = 11/2
(3/2)*(x-3) = (5/2)*(x-4)
Expand brackets in the left part
3/2x-3 = (5/2)*(x-4)
Expand brackets in the right part
3/2x-3 = 5/2x-4
Move free summands (without x)
from left part to right part, we given:
$$\frac{3 x}{2} = \frac{5 x}{2} - \frac{11}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = - \frac{11}{2}$$
Divide both parts of the equation by -1
x = -11/2 / (-1)
We get the answer: x = 11/2
Sum and product of roots
[src]
sum
11/2
$$\frac{11}{2}$$
=
11/2
$$\frac{11}{2}$$
product
11/2
$$\frac{11}{2}$$
=
11/2
$$\frac{11}{2}$$
11/2