Expand the expression in the equation
$$\left(6 x + \frac{6}{5}\right) \left(15 x - 1\right) = 0$$
We get the quadratic equation
$$90 x^{2} + 12 x - \frac{6}{5} = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 90$$
$$b = 12$$
$$c = - \frac{6}{5}$$
, then
D = b^2 - 4 * a * c =
(12)^2 - 4 * (90) * (-6/5) = 576
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = \frac{1}{15}$$
$$x_{2} = - \frac{1}{5}$$