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(11x-5)^2-(10x-1)^2-(3x-20)*(7x+10)=124 equation

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Numerical solution:

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The solution

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          2             2                              
(11*x - 5)  - (10*x - 1)  - (3*x - 20)*(7*x + 10) = 124
$$- \left(3 x - 20\right) \left(7 x + 10\right) + \left(- \left(10 x - 1\right)^{2} + \left(11 x - 5\right)^{2}\right) = 124$$
Detail solution
Given the equation:
(11*x-5)^2-(10*x-1)^2-(3*x-20)*(7*x+10) = 124

Expand expressions:
24 - 90*x + 21*x^2 - (3*x - 20)*(7*x + 10) = 124

24 - 90*x + 21*x^2 + 200 - 21*x^2 + 110*x = 124

Reducing, you get:
100 + 20*x = 0

Move free summands (without x)
from left part to right part, we given:
$$20 x = -100$$
Divide both parts of the equation by 20
x = -100 / (20)

We get the answer: x = -5
The graph
Rapid solution [src]
x1 = -5
$$x_{1} = -5$$
x1 = -5
Sum and product of roots [src]
sum
-5
$$-5$$
=
-5
$$-5$$
product
-5
$$-5$$
=
-5
$$-5$$
-5
Numerical answer [src]
x1 = -5.0
x1 = -5.0