Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation tan(x/3)+1=0
- Equation (3x-10)-(8x-5)=10.
- Equation x^(3/2)=2,6*10^(-27)
- Equation 20*x^4+158,9*x-1=0
- Express {x} in terms of y where:
- -8*x-6*y=12
- -20*x+2*y=-20
- -19*x+8*y=13
- -18*x-4*y=18
-
Identical expressions
- |x+ thirteen |= six
- module of x plus 13| equally 6
- module of x plus thirteen | equally six
-
Similar expressions
- |(x+1)3|=X3
- |x+(13)|-|x-4|=56
- |x-13|=6
|x+13|=6 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x + 13 \geq 0$$
or
$$-13 \leq x \wedge x < \infty$$
we get the equation
$$\left(x + 13\right) - 6 = 0$$
after simplifying we get
$$x + 7 = 0$$
the solution in this interval:
$$x_{1} = -7$$
2.
$$x + 13 < 0$$
or
$$-\infty < x \wedge x < -13$$
we get the equation
$$\left(- x - 13\right) - 6 = 0$$
after simplifying we get
$$- x - 19 = 0$$
the solution in this interval:
$$x_{2} = -19$$
The final answer:
$$x_{1} = -7$$
$$x_{2} = -19$$
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x + 13 \geq 0$$
or
$$-13 \leq x \wedge x < \infty$$
we get the equation
$$\left(x + 13\right) - 6 = 0$$
after simplifying we get
$$x + 7 = 0$$
the solution in this interval:
$$x_{1} = -7$$
2.
$$x + 13 < 0$$
or
$$-\infty < x \wedge x < -13$$
we get the equation
$$\left(- x - 13\right) - 6 = 0$$
after simplifying we get
$$- x - 19 = 0$$
the solution in this interval:
$$x_{2} = -19$$
The final answer:
$$x_{1} = -7$$
$$x_{2} = -19$$
Sum and product of roots
[src]
sum
-19 - 7
$$-19 - 7$$
=
-26
$$-26$$
product
-19*(-7)
$$- -133$$
=
133
$$133$$
133