Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation x+7*4=40
-
Equation -x^3+4*x^2+4*x-16=0
-
Equation x/7=6
-
Equation 2x-cosx=0
- Express {x} in terms of y where:
- 13*x-12*y=10
- -12*x-19*y=16
- 4*x-7*y=11
- 18*x-11*y=13
- Integral of d{x}:
- |x+1|
-
Identical expressions
- |x+ one |= three
- module of x plus 1| equally 3
- module of x plus one | equally three
-
Similar expressions
- |x-1|=3
|x+1|=3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x + 1 \geq 0$$
or
$$-1 \leq x \wedge x < \infty$$
we get the equation
$$\left(x + 1\right) - 3 = 0$$
after simplifying we get
$$x - 2 = 0$$
the solution in this interval:
$$x_{1} = 2$$
2.
$$x + 1 < 0$$
or
$$-\infty < x \wedge x < -1$$
we get the equation
$$\left(- x - 1\right) - 3 = 0$$
after simplifying we get
$$- x - 4 = 0$$
the solution in this interval:
$$x_{2} = -4$$
The final answer:
$$x_{1} = 2$$
$$x_{2} = -4$$
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x + 1 \geq 0$$
or
$$-1 \leq x \wedge x < \infty$$
we get the equation
$$\left(x + 1\right) - 3 = 0$$
after simplifying we get
$$x - 2 = 0$$
the solution in this interval:
$$x_{1} = 2$$
2.
$$x + 1 < 0$$
or
$$-\infty < x \wedge x < -1$$
we get the equation
$$\left(- x - 1\right) - 3 = 0$$
after simplifying we get
$$- x - 4 = 0$$
the solution in this interval:
$$x_{2} = -4$$
The final answer:
$$x_{1} = 2$$
$$x_{2} = -4$$
Sum and product of roots
[src]
sum
-4 + 2
$$-4 + 2$$
=
-2
$$-2$$
product
-4*2
$$- 8$$
=
-8
$$-8$$
-8
The graph