Mister Exam
Other calculators
-
How to use it?
- Equation:
- Equation a*x=b
-
Equation x^2-x+8=0
-
Equation 3x^2-2x=0
- Equation x^2+y^2=1
- Express {x} in terms of y where:
- -4*x+7*y=-16
- -16*x+3*y=17
- -17*x+16*y=-19
- 18*x-6*y=7
-
Identical expressions
- | seventeen -(3x- nine)|== eleven
- module of 17 minus (3x minus 9)| equally equally 11
- module of seventeen minus (3x minus nine)| equally equally eleven
- |17-3x-9|==11
-
Similar expressions
- |17+(3x-9)|==11
- |17-(3x+9)|==11
|17-(3x-9)|==11 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$3 x - 26 \geq 0$$
or
$$\frac{26}{3} \leq x \wedge x < \infty$$
we get the equation
$$3 x - 26 = 0$$
after simplifying we get
$$3 x - 26 = 0$$
the solution in this interval:
$$x_{1} = \frac{26}{3}$$
2.
$$3 x - 26 < 0$$
or
$$-\infty < x \wedge x < \frac{26}{3}$$
we get the equation
$$26 - 3 x = 0$$
after simplifying we get
$$26 - 3 x = 0$$
the solution in this interval:
$$x_{2} = \frac{26}{3}$$
but x2 not in the inequality interval
The final answer:
$$x_{1} = \frac{26}{3}$$
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$3 x - 26 \geq 0$$
or
$$\frac{26}{3} \leq x \wedge x < \infty$$
we get the equation
$$3 x - 26 = 0$$
after simplifying we get
$$3 x - 26 = 0$$
the solution in this interval:
$$x_{1} = \frac{26}{3}$$
2.
$$3 x - 26 < 0$$
or
$$-\infty < x \wedge x < \frac{26}{3}$$
we get the equation
$$26 - 3 x = 0$$
after simplifying we get
$$26 - 3 x = 0$$
the solution in this interval:
$$x_{2} = \frac{26}{3}$$
but x2 not in the inequality interval
The final answer:
$$x_{1} = \frac{26}{3}$$
Sum and product of roots
[src]
sum
26/3
$$\frac{26}{3}$$
=
26/3
$$\frac{26}{3}$$
product
26/3
$$\frac{26}{3}$$
=
26/3
$$\frac{26}{3}$$
26/3