Mister Exam
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- Equation:
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Equation 15-x=8
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Equation x^2+3*x+9=0
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Equation x^2-16*x+64=0
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Equation x^2-6x-7=0
- Express {x} in terms of y where:
- 9*x-8*y=-6
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Identical expressions
- -x*((sqrt(three)/ two)- one)= one
- minus x multiply by (( square root of (3) divide by 2) minus 1) equally 1
- minus x multiply by (( square root of (three) divide by two) minus one) equally one
- -x*((√(3)/2)-1)=1
- -x((sqrt(3)/2)-1)=1
- -xsqrt3/2-1=1
- -x*((sqrt(3) divide by 2)-1)=1
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Similar expressions
- -x*((sqrt(3)/2)+1)=1
- x*((sqrt(3)/2)-1)=1
-x*((sqrt(3)/2)-1)=1 equation
The teacher will be very surprised to see your correct solution 😉
The solution
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[src]
/ ___ \ |\/ 3 | -x*|----- - 1| = 1 \ 2 /
$$- x \left(-1 + \frac{\sqrt{3}}{2}\right) = 1$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Move free summands (without x)
from left part to right part, we given:
$$- x \left(-1 + \frac{\sqrt{3}}{2}\right) + 1 = 2$$
Divide both parts of the equation by (1 - x*(-1 + sqrt(3)/2))/x
We get the answer: x = 4 + 2*sqrt(3)
-x*((sqrt(3)/2)-1) = 1
Expand brackets in the left part
-xsqrt/2+3/2)-1) = 1
Move free summands (without x)
from left part to right part, we given:
$$- x \left(-1 + \frac{\sqrt{3}}{2}\right) + 1 = 2$$
Divide both parts of the equation by (1 - x*(-1 + sqrt(3)/2))/x
x = 2 / ((1 - x*(-1 + sqrt(3)/2))/x)
We get the answer: x = 4 + 2*sqrt(3)
Sum and product of roots
[src]
sum
___ 4 + 2*\/ 3
$$2 \sqrt{3} + 4$$
=
___ 4 + 2*\/ 3
$$2 \sqrt{3} + 4$$
product
___ 4 + 2*\/ 3
$$2 \sqrt{3} + 4$$
=
___ 4 + 2*\/ 3
$$2 \sqrt{3} + 4$$
4 + 2*sqrt(3)