Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^3=2
-
Equation x^2-20=0
-
Equation x-32/4=50
- Equation ax=b
- Express {x} in terms of y where:
- -4*x+7*y=-16
- 12*x-20*y=9
- -1*x-20*y=1
- -5*x-12*y=13
-
Identical expressions
- - three (one -x)=- four (7x- five)
- minus 3(1 minus x) equally minus 4(7x minus 5)
- minus three (one minus x) equally minus four (7x minus five)
- -31-x=-47x-5
-
Similar expressions
- -3(1-x)=-4(7x+5)
- -3(1-x)=+4(7x-5)
- (62+2*x)*exp(-31-x)-(x+31)^2*exp(-31-x)=0
- -31-x=-19
- (x-3)*(1-x)=0
- 3(1-x)=-4(7x-5)
- -3(1+x)=-4(7x-5)
-3(1-x)=-4(7x-5) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
-3*(1 - x) = -4*(7*x - 5)
$$- 3 \left(1 - x\right) = - 4 \left(7 x - 5\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$3 x = 23 - 28 x$$
Move the summands with the unknown x
from the right part to the left part:
$$31 x = 23$$
Divide both parts of the equation by 31
We get the answer: x = 23/31
-3*(1-x) = -4*(7*x-5)
Expand brackets in the left part
-3*1+3*x = -4*(7*x-5)
Expand brackets in the right part
-3*1+3*x = -4*7*x+4*5
Move free summands (without x)
from left part to right part, we given:
$$3 x = 23 - 28 x$$
Move the summands with the unknown x
from the right part to the left part:
$$31 x = 23$$
Divide both parts of the equation by 31
x = 23 / (31)
We get the answer: x = 23/31
Sum and product of roots
[src]
sum
23 -- 31
$$\frac{23}{31}$$
=
23 -- 31
$$\frac{23}{31}$$
product
23 -- 31
$$\frac{23}{31}$$
=
23 -- 31
$$\frac{23}{31}$$
23/31