Mister Exam
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How to use it?
- Equation:
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Equation ((1/5))^(x)^(2)*5^(2*x+2)=(1/5)^(6)
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Equation x^3-x^2-x-1=0
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Equation -x=3
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Equation x-6/2-x/3=3
- Express {x} in terms of y where:
- 9*x+10*y=5
- -4*x+19*y=-13
- -5*x-6*y=-1
- -7*x+15*y=18
- Derivative of:
- -7x+3
- Graphing y =:
- -7x+3
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Identical expressions
- -7x+ three = thirty -2x
- minus 7x plus 3 equally 30 minus 2x
- minus 7x plus three equally thirty minus 2x
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Similar expressions
- -7x+3=30+2x
- 7x+3=30-2x
- x^2-7*x+3=0
- 4(x-8)i-7(x+3)=0
- -5(x-7)=30-(2x+1)
- -7x-3=30-2x
- 4*x^2-7*x+3=0
- -5*(z-7)=30-(2*x+1)
-7x+3=30-2x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- 7 x = 27 - 2 x$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-5\right) x = 27$$
Divide both parts of the equation by -5
We get the answer: x = -27/5
-7*x+3 = 30-2*x
Move free summands (without x)
from left part to right part, we given:
$$- 7 x = 27 - 2 x$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-5\right) x = 27$$
Divide both parts of the equation by -5
x = 27 / (-5)
We get the answer: x = -27/5
Sum and product of roots
[src]
sum
-27/5
$$- \frac{27}{5}$$
=
-27/5
$$- \frac{27}{5}$$
product
-27/5
$$- \frac{27}{5}$$
=
-27/5
$$- \frac{27}{5}$$
-27/5
The graph