Mister Exam
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How to use it?
- Equation:
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Equation 1/(x-1)^2+2/(x-1)-3=0
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Equation 4(5x+2)=10(2x-3)+15
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Equation ((57.6/(150-x))^0.15)*((150+x)+10)/171.712=1
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Equation x^2-7*x+12=0
- Express {x} in terms of y where:
- 4*x+2*y=5
- -17*x+1*y=-11
- -17*x+18*y=10
- 6*x+17*y=-11
- Derivative of:
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5x-3
- Graphing y =:
- 5x-3
- Integral of d{x}:
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5x-3
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Identical expressions
- -7x+ nine =5x- three
- minus 7x plus 9 equally 5x minus 3
- minus 7x plus nine equally 5x minus three
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Similar expressions
- -7x-9=5x-3
- 18/(x^2-7*x+9)=0
- (x-4)/3+(2(x+1))/4-1=(5(x-3))/2+2x-(11x+43)/6
- 5^(x-1)-5^(x-3)=24/25
- -7x+9=5x+3
- (-5*x-3)*(2*x-1)-a=0
- 7x+9=5x-3
-7x+9=5x-3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- 7 x = 5 x - 12$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-12\right) x = -12$$
Divide both parts of the equation by -12
We get the answer: x = 1
-7*x+9 = 5*x-3
Move free summands (without x)
from left part to right part, we given:
$$- 7 x = 5 x - 12$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-12\right) x = -12$$
Divide both parts of the equation by -12
x = -12 / (-12)
We get the answer: x = 1