Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation 3*x^2+6*x+3=0
-
Equation -4x+9=-19
-
Equation -4x+3=2x
- Equation 3*x^3-27*x=0
- Express {x} in terms of y where:
- 19*x-18*y=15
- 13*x-13*y=-4
- 19*x-20*y=-12
- 12*x+7*y=15
- Sum of series:
-
16
- Derivative of:
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16
- Integral of d{x}:
-
16
-
Identical expressions
- log(x)/log(four)= sixteen
- logarithm of (x) divide by logarithm of (4) equally 16
- logarithm of (x) divide by logarithm of (four) equally sixteen
- logx/log4=16
- log(x) divide by log(4)=16
log(x)/log(4)=16 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
log(x) ------ = 16 log(4)
$$\frac{\log{\left(x \right)}}{\log{\left(4 \right)}} = 16$$
Detail solution
Given the equation
$$\frac{\log{\left(x \right)}}{\log{\left(4 \right)}} = 16$$
$$\frac{\log{\left(x \right)}}{\log{\left(4 \right)}} = 16$$
Let's divide both parts of the equation by the multiplier of log =1/log(4)
$$\log{\left(x \right)} = 16 \log{\left(4 \right)}$$
This equation is of the form:
By definition log
then
$$x = e^{\frac{16}{\frac{1}{\log{\left(4 \right)}}}}$$
simplify
$$x = 4294967296$$
$$\frac{\log{\left(x \right)}}{\log{\left(4 \right)}} = 16$$
$$\frac{\log{\left(x \right)}}{\log{\left(4 \right)}} = 16$$
Let's divide both parts of the equation by the multiplier of log =1/log(4)
$$\log{\left(x \right)} = 16 \log{\left(4 \right)}$$
This equation is of the form:
log(v)=p
By definition log
v=e^p
then
$$x = e^{\frac{16}{\frac{1}{\log{\left(4 \right)}}}}$$
simplify
$$x = 4294967296$$
Sum and product of roots
[src]
sum
4294967296
$$4294967296$$
=
4294967296
$$4294967296$$
product
4294967296
$$4294967296$$
=
4294967296
$$4294967296$$
4294967296
Numerical answer
[src]
x1 = 4294967296.0
x2 = 4294967296.0 - 1.36806337186136e-18*i
x2 = 4294967296.0 - 1.36806337186136e-18*i