Mister Exam
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How to use it?
- Equation:
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Equation (-5*x-3)*(2*x-1)=0
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Equation 4-6*(x+2)=3-5*x
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Equation tg(x)=-1
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Equation x^2+5x-14=0
- Express {x} in terms of y where:
- 4*x+3*y=-15
- -18*x-3*y=2
- 16*x-20*y=-4
- (x^2+y^2-1)^3-x^2*y^3=0
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Identical expressions
- log(two x+ one)(two x^2-8x+ fifteen)=2
- logarithm of (2x plus 1)(2x squared minus 8x plus 15) equally 2
- logarithm of (two x plus one)(two x squared minus 8x plus fifteen) equally 2
- log(2x+1)(2x2-8x+15)=2
- log2x+12x2-8x+15=2
- log(2x+1)(2x²-8x+15)=2
- log(2x+1)(2x to the power of 2-8x+15)=2
- log2x+12x^2-8x+15=2
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Similar expressions
- log(2x+1)(2x^2+8x+15)=2
- log(2x+1)(2x^2-8x-15)=2
- log(2x-1)(2x^2-8x+15)=2
log(2x+1)(2x^2-8x+15)=2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
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[src]
/ 2 \ log(2*x + 1)*\2*x - 8*x + 15/ = 2
$$\left(\left(2 x^{2} - 8 x\right) + 15\right) \log{\left(2 x + 1 \right)} = 2$$
Numerical answer
[src]
x1 = 1.95054513113234 + 1.73301873940529*i
x2 = 0.0744108375235156
x3 = 1.95054513113234 - 1.73301873940529*i
x3 = 1.95054513113234 - 1.73301873940529*i