Mister Exam
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How to use it?
- Equation:
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Equation (x-1)*(x^2+8*x+16)=6*(x+4)
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Equation x^2-5*x-1=0
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Equation 2x+1-20x+15=6x+4
- Equation 815-13*b=295
- Express {x} in terms of y where:
- 20*x+19*y=-6
- -5*x+6*y=6
- -12*x-19*y=11
- 9*x+14*y=13
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Identical expressions
- log(three)-x5- one / two = zero
- logarithm of (3) minus x5 minus 1 divide by 2 equally 0
- logarithm of (three) minus x5 minus one divide by two equally zero
- log3-x5-1/2=0
- log(3)-x5-1/2=O
- log(3)-x5-1 divide by 2=0
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Similar expressions
- log(3)+x5-1/2=0
- log(3)-x5+1/2=0
log(3)-x5-1/2=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
log(3) - x5 - 1/2 = 0
$$\left(- x_{5} + \log{\left(3 \right)}\right) - \frac{1}{2} = 0$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Move free summands (without x5)
from left part to right part, we given:
$$- x_{5} + \log{\left(3 \right)} = \frac{1}{2}$$
Divide both parts of the equation by (-x5 + log(3))/x5
We get the answer: x5 = -1/2 + log(3)
log(3)-x5-1/2 = 0
Expand brackets in the left part
log3-x5-1/2 = 0
Move free summands (without x5)
from left part to right part, we given:
$$- x_{5} + \log{\left(3 \right)} = \frac{1}{2}$$
Divide both parts of the equation by (-x5 + log(3))/x5
x5 = 1/2 / ((-x5 + log(3))/x5)
We get the answer: x5 = -1/2 + log(3)
Rapid solution
[src]
x51 = -1/2 + log(3)
$$x_{51} = - \frac{1}{2} + \log{\left(3 \right)}$$
x51 = -1/2 + log(3)
Sum and product of roots
[src]
sum
-1/2 + log(3)
$$- \frac{1}{2} + \log{\left(3 \right)}$$
=
-1/2 + log(3)
$$- \frac{1}{2} + \log{\left(3 \right)}$$
product
-1/2 + log(3)
$$- \frac{1}{2} + \log{\left(3 \right)}$$
=
-1/2 + log(3)
$$- \frac{1}{2} + \log{\left(3 \right)}$$
-1/2 + log(3)