Mister Exam
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How to use it?
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- Express {x} in terms of y where:
- -2*x-5*y=16
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- Graphing y =:
- log1/5x
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Identical expressions
- log5(three -2x)=log1/5x
- logarithm of 5(3 minus 2x) equally logarithm of 1 divide by 5x
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Similar expressions
- log(1/5)(x^2−4x+8)=−1
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- log5(3+2x)=log1/5x
log5(3-2x)=log1/5x equation
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The solution
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log(3 - 2*x) log(1) ------------ = ------*x log(5) 5
$$\frac{\log{\left(3 - 2 x \right)}}{\log{\left(5 \right)}} = x \frac{\log{\left(1 \right)}}{5}$$
Detail solution
Given the equation
$$\frac{\log{\left(3 - 2 x \right)}}{\log{\left(5 \right)}} = x \frac{\log{\left(1 \right)}}{5}$$
$$\frac{\log{\left(3 - 2 x \right)}}{\log{\left(5 \right)}} = 0$$
Let's divide both parts of the equation by the multiplier of log =1/log(5)
$$\log{\left(3 - 2 x \right)} = 0$$
This equation is of the form:
By definition log
then
$$3 - 2 x = e^{\frac{0}{\frac{1}{\log{\left(5 \right)}}}}$$
simplify
$$3 - 2 x = 1$$
$$- 2 x = -2$$
$$x = 1$$
$$\frac{\log{\left(3 - 2 x \right)}}{\log{\left(5 \right)}} = x \frac{\log{\left(1 \right)}}{5}$$
$$\frac{\log{\left(3 - 2 x \right)}}{\log{\left(5 \right)}} = 0$$
Let's divide both parts of the equation by the multiplier of log =1/log(5)
$$\log{\left(3 - 2 x \right)} = 0$$
This equation is of the form:
log(v)=p
By definition log
v=e^p
then
$$3 - 2 x = e^{\frac{0}{\frac{1}{\log{\left(5 \right)}}}}$$
simplify
$$3 - 2 x = 1$$
$$- 2 x = -2$$
$$x = 1$$