Mister Exam
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How to use it?
- Equation:
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Equation x^3=x^2+2x
- Equation x^3+6x^2-x-6=0
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Equation (x-1)*(x^2+8*x+16)=6*(x+4)
- Equation x^3+2*x^2-36*x-72=0
- Express {x} in terms of y where:
- -13*x-15*y=-9
- 12*x+10*y=17
- 14*x+7*y=-4
- -15*x-16*y=12
- Sum of series:
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1/2
- Derivative of:
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1/2
- Integral of d{x}:
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1/2
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Identical expressions
- log4(six - two x)= one /2
- logarithm of 4(6 minus 2x) equally 1 divide by 2
- logarithm of 4(six minus two x) equally one divide by 2
- log46-2x=1/2
- log4(6-2x)=1 divide by 2
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Similar expressions
- log4(6+2x)=1/2
log4(6-2x)=1/2 equation
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The solution
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log(6 - 2*x) ------------ = 1/2 log(4)
$$\frac{\log{\left(6 - 2 x \right)}}{\log{\left(4 \right)}} = \frac{1}{2}$$
Detail solution
Given the equation
$$\frac{\log{\left(6 - 2 x \right)}}{\log{\left(4 \right)}} = \frac{1}{2}$$
$$\frac{\log{\left(6 - 2 x \right)}}{\log{\left(4 \right)}} = \frac{1}{2}$$
Let's divide both parts of the equation by the multiplier of log =1/log(4)
$$\log{\left(6 - 2 x \right)} = \frac{\log{\left(4 \right)}}{2}$$
This equation is of the form:
By definition log
then
$$6 - 2 x = e^{\frac{1}{2 \frac{1}{\log{\left(4 \right)}}}}$$
simplify
$$6 - 2 x = 2$$
$$- 2 x = -4$$
$$x = 2$$
$$\frac{\log{\left(6 - 2 x \right)}}{\log{\left(4 \right)}} = \frac{1}{2}$$
$$\frac{\log{\left(6 - 2 x \right)}}{\log{\left(4 \right)}} = \frac{1}{2}$$
Let's divide both parts of the equation by the multiplier of log =1/log(4)
$$\log{\left(6 - 2 x \right)} = \frac{\log{\left(4 \right)}}{2}$$
This equation is of the form:
log(v)=p
By definition log
v=e^p
then
$$6 - 2 x = e^{\frac{1}{2 \frac{1}{\log{\left(4 \right)}}}}$$
simplify
$$6 - 2 x = 2$$
$$- 2 x = -4$$
$$x = 2$$