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Similar expressions
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lg(x-1)+lg(x-1)=0 equation
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The solution
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log(x - 1) + log(x - 1) = 0
$$\log{\left(x - 1 \right)} + \log{\left(x - 1 \right)} = 0$$
Detail solution
Given the equation
$$\log{\left(x - 1 \right)} + \log{\left(x - 1 \right)} = 0$$
$$2 \log{\left(x - 1 \right)} = 0$$
Let's divide both parts of the equation by the multiplier of log =2
$$\log{\left(x - 1 \right)} = 0$$
This equation is of the form:
By definition log
then
$$x - 1 = e^{\frac{0}{2}}$$
simplify
$$x - 1 = 1$$
$$x = 2$$
$$\log{\left(x - 1 \right)} + \log{\left(x - 1 \right)} = 0$$
$$2 \log{\left(x - 1 \right)} = 0$$
Let's divide both parts of the equation by the multiplier of log =2
$$\log{\left(x - 1 \right)} = 0$$
This equation is of the form:
log(v)=p
By definition log
v=e^p
then
$$x - 1 = e^{\frac{0}{2}}$$
simplify
$$x - 1 = 1$$
$$x = 2$$