Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation -6x+2=-x+22
- Equation x^2-x-72=0
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Equation x-5(x+3)=5
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Equation 5x+8=-12
- Express {x} in terms of y where:
- 7*x-2*y=18
- -10*x-12*y=-10
- -2*x+2*y=4
- 11*x+8*y=-16
- Derivative of:
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(2*x-3)^2
- Graphing y =:
- (2*x-3)^2
- Canonical form:
- (2*x-3)^2
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Identical expressions
- (four *x- five)*(x+ three)=(two *x- three)^ two
- (4 multiply by x minus 5) multiply by (x plus 3) equally (2 multiply by x minus 3) squared
- (four multiply by x minus five) multiply by (x plus three) equally (two multiply by x minus three) to the power of two
- (4*x-5)*(x+3)=(2*x-3)2
- 4*x-5*x+3=2*x-32
- (4*x-5)*(x+3)=(2*x-3)²
- (4*x-5)*(x+3)=(2*x-3) to the power of 2
- (4x-5)(x+3)=(2x-3)^2
- (4x-5)(x+3)=(2x-3)2
- 4x-5x+3=2x-32
- 4x-5x+3=2x-3^2
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Similar expressions
- (4x-5)(x+3)=(2x-5)(2x+5)
- (4*x-5)*(x-3)=(2*x-3)^2
- (4*x+5)*(x+3)=(2*x-3)^2
- (4*x-5)*(x+3)=(2*x+3)^2
(4*x-5)*(x+3)=(2*x-3)^2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2 (4*x - 5)*(x + 3) = (2*x - 3)
$$\left(x + 3\right) \left(4 x - 5\right) = \left(2 x - 3\right)^{2}$$
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$19 x = 24$$
Divide both parts of the equation by 19
We get the answer: x = 24/19
(4*x-5)*(x+3) = (2*x-3)^2
Expand expressions:
-15 + 4*x^2 + 7*x = (2*x-3)^2
(4*x-5)*(x+3) = 9 - 12*x + 4*x^2
Reducing, you get:
-24 + 19*x = 0
Move free summands (without x)
from left part to right part, we given:
$$19 x = 24$$
Divide both parts of the equation by 19
x = 24 / (19)
We get the answer: x = 24/19
Sum and product of roots
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sum
24 -- 19
$$\frac{24}{19}$$
=
24 -- 19
$$\frac{24}{19}$$
product
24 -- 19
$$\frac{24}{19}$$
=
24 -- 19
$$\frac{24}{19}$$
24/19