(4-x^2)^(1/2) equation
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The solution
Detail solution
$$\sqrt{4 - x^{2}} = 0$$
transform
$$4 - x^{2} = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = -1$$
$$b = 0$$
$$c = 4$$
, then
D = b^2 - 4 * a * c =
(0)^2 - 4 * (-1) * (4) = 16
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = -2$$
$$x_{2} = 2$$
$$x_{1} = -2$$
$$x_{2} = 2$$
Sum and product of roots
[src]
$$-2 + 2$$
$$0$$
$$- 4$$
$$-4$$