Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 3*x^2-12*x+12=0
-
Equation 5(x-2,2)=7x
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Equation 4*x^2-11*x-3=0
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Equation 10x+1=6x
- Express {x} in terms of y where:
- 4*x+5*y=7
- 12*x+14*y=9
- -13*x+10*y=-18
- 12*x+10*y=14
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Identical expressions
- four , eight -(two , four -5b)=b- eight , four
- 4,8 minus (2,4 minus 5b) equally b minus 8,4
- four , eight minus (two , four minus 5b) equally b minus eight , four
- 4,8-2,4-5b=b-8,4
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Similar expressions
- 4,8+(2,4-5b)=b-8,4
- 4,8-(2,4+5b)=b-8,4
- 4,8-(2,4-5b)=b+8,4
4,8-(2,4-5b)=b-8,4 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
24/5 + -12/5 + 5*b = b - 42/5
$$\left(5 b - \frac{12}{5}\right) + \frac{24}{5} = b - \frac{42}{5}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move free summands (without b)
from left part to right part, we given:
$$5 b = b - \frac{54}{5}$$
Move the summands with the unknown b
from the right part to the left part:
$$4 b = - \frac{54}{5}$$
Divide both parts of the equation by 4
We get the answer: b = -27/10
(24/5)-((12/5)-5*b) = b-(42/5)
Expand brackets in the left part
24/5-12/5-5*b) = b-(42/5)
Expand brackets in the right part
24/5-12/5-5*b) = b-42/5
Looking for similar summands in the left part:
12/5 + 5*b = b-42/5
Move free summands (without b)
from left part to right part, we given:
$$5 b = b - \frac{54}{5}$$
Move the summands with the unknown b
from the right part to the left part:
$$4 b = - \frac{54}{5}$$
Divide both parts of the equation by 4
b = -54/5 / (4)
We get the answer: b = -27/10
Sum and product of roots
[src]
sum
-27 ---- 10
$$- \frac{27}{10}$$
=
-27 ---- 10
$$- \frac{27}{10}$$
product
-27 ---- 10
$$- \frac{27}{10}$$
=
-27 ---- 10
$$- \frac{27}{10}$$
-27/10