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4/7x^2=28 equation

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Numerical solution:

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The solution

You have entered [src]
   2     
4*x      
---- = 28
 7       
$$\frac{4 x^{2}}{7} = 28$$
Detail solution
Move right part of the equation to
left part with negative sign.

The equation is transformed from
$$\frac{4 x^{2}}{7} = 28$$
to
$$\frac{4 x^{2}}{7} - 28 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = \frac{4}{7}$$
$$b = 0$$
$$c = -28$$
, then
D = b^2 - 4 * a * c = 

(0)^2 - 4 * (4/7) * (-28) = 64

Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)

x2 = (-b - sqrt(D)) / (2*a)

or
$$x_{1} = 7$$
$$x_{2} = -7$$
Vieta's Theorem
rewrite the equation
$$\frac{4 x^{2}}{7} = 28$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} - 49 = 0$$
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = -49$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = 0$$
$$x_{1} x_{2} = -49$$
The graph
Rapid solution [src]
x1 = -7
$$x_{1} = -7$$
x2 = 7
$$x_{2} = 7$$
x2 = 7
Sum and product of roots [src]
sum
-7 + 7
$$-7 + 7$$
=
0
$$0$$
product
-7*7
$$- 49$$
=
-49
$$-49$$
-49
Numerical answer [src]
x1 = 7.0
x2 = -7.0
x2 = -7.0