Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x-1/5-x=2/9
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Equation 1/(x-4)^2-7/x-4+10=0
- Equation (2*x-1)^2-3^2=0
- Equation x⁴-2x²-8=0
- Express {x} in terms of y where:
- sqrt(1-x)^2+(4-y)^2=0
- lnx+sin(y/x+2x)=4
- cos(x-y)+(4-y)/(x^2)+ln(1-x^2)+tg2y+2=0
- y^t=(y/x)^2+(y/x)+4
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Identical expressions
- five (x- twelve)= six (- ten)-x
- 5(x minus 12) equally 6( minus 10) minus x
- five (x minus twelve) equally six ( minus ten) minus x
- 5x-12=6-10-x
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Similar expressions
- 720:(5*x-12)-56=34
- 5(x-12)=6(10)-x
- 20*x+60=-15x-12
- 5*(5x^2-12x)=6+13*(5x-12)
- 5(x-12)=6(-10)+x
- 36x^6-183x^5+109x^4-202x^3-39x^2+65x-12=0
- 5(x+12)=6(-10)-x
5(x-12)=6(-10)-x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$5 x = - x$$
Move the summands with the unknown x
from the right part to the left part:
$$6 x = 0$$
Divide both parts of the equation by 6
We get the answer: x = 0
5*(x-12) = 6*(-10)-x
Expand brackets in the left part
5*x-5*12 = 6*(-10)-x
Expand brackets in the right part
5*x-5*12 = -6*10-x
Move free summands (without x)
from left part to right part, we given:
$$5 x = - x$$
Move the summands with the unknown x
from the right part to the left part:
$$6 x = 0$$
Divide both parts of the equation by 6
x = 0 / (6)
We get the answer: x = 0