Mister Exam
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How to use it?
- Equation:
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Equation x^2=5
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Equation k^2+k=0
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Equation 5x=0
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Equation x^2-15=2x
- Express {x} in terms of y where:
- -4*x+3*y=9
- -2*x-19*y=-11
- -5*x+15*y=-15
- -1*x+7*y=-11
- Integral of d{x}:
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9x
- Derivative of:
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9x
- Canonical form:
- 9x
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Identical expressions
- five (x- three , six)=9x
- 5(x minus 3,6) equally 9x
- five (x minus three , six) equally 9x
- 5x-3,6=9x
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Similar expressions
- 5(x+3,6)=9x
- x^3+9*x^2+27*x+27=0
- 5*x^2+9*x=0
5(x-3,6)=9x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Move free summands (without x)
from left part to right part, we given:
$$5 x = 9 x + 18$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-4\right) x = 18$$
Divide both parts of the equation by -4
We get the answer: x = -9/2
5*(x-(18/5)) = 9*x
Expand brackets in the left part
5*x+5*18/5) = 9*x
Move free summands (without x)
from left part to right part, we given:
$$5 x = 9 x + 18$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-4\right) x = 18$$
Divide both parts of the equation by -4
x = 18 / (-4)
We get the answer: x = -9/2
Sum and product of roots
[src]
sum
-9/2
$$- \frac{9}{2}$$
=
-9/2
$$- \frac{9}{2}$$
product
-9/2
$$- \frac{9}{2}$$
=
-9/2
$$- \frac{9}{2}$$
-9/2
The graph