Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation 3^x=27
-
Equation x^2=12
-
Equation 12-x^2=11
-
Equation -sin(x)=0
- Express {x} in terms of y where:
- -5*x-6*y=-1
- -17*x-15*y=-17
- -2*x+7*y=-14
- -11*x-1*y=15
-
Identical expressions
- five (x- three)= fourteen - two (seven -2x)
- 5(x minus 3) equally 14 minus 2(7 minus 2x)
- five (x minus three) equally fourteen minus two (seven minus 2x)
- 5x-3=14-27-2x
-
Similar expressions
- (2x+19)*(2x+14)-((27-(2x+17)^3))/((((√(-2x-18)^2)+4)))=(-2x-17)*|x+8|-25
- (2*x+19)*(2*x+14)-((27-(2*x+17)^3))/((((sqrt(-2*x-18)^2)+4)))=(-2*x-17)*(|x+8|)-25
- x^2-5*x-36=0
- 5(x+3)=14-2(7-2x)
- 2log0,5(x)-3=-log0,5(x)
- 5(x-3)=14+2(7-2x)
- 5(x-3)=14-2(7+2x)
5(x-3)=14-2(7-2x) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
5*(x - 3) = 14 - 2*(7 - 2*x)
$$5 \left(x - 3\right) = 14 - 2 \left(7 - 2 x\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$5 x = 4 x + 15$$
Move the summands with the unknown x
from the right part to the left part:
$$x = 15$$
We get the answer: x = 15
5*(x-3) = 14-2*(7-2*x)
Expand brackets in the left part
5*x-5*3 = 14-2*(7-2*x)
Expand brackets in the right part
5*x-5*3 = 14-2*7+2*2*x
Looking for similar summands in the right part:
-15 + 5*x = 4*x
Move free summands (without x)
from left part to right part, we given:
$$5 x = 4 x + 15$$
Move the summands with the unknown x
from the right part to the left part:
$$x = 15$$
We get the answer: x = 15
The graph