Mister Exam
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How to use it?
- Equation:
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Equation 2x^2-8=0
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Equation 8x-15=-12+5x
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Equation 5*(x+9)=-8
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Equation 7(x-1)=3x
- Express {x} in terms of y where:
- 10*x+13*y=-16
- -2*x-7*y=3
- -15*x-15*y=12
- 10*x-13*y=16
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Identical expressions
- five *x-(three + two *x- two *x^ two)= two *x^ two - seven *x+ seventeen
- 5 multiply by x minus (3 plus 2 multiply by x minus 2 multiply by x squared ) equally 2 multiply by x squared minus 7 multiply by x plus 17
- five multiply by x minus (three plus two multiply by x minus two multiply by x to the power of two) equally two multiply by x to the power of two minus seven multiply by x plus seventeen
- 5*x-(3+2*x-2*x2)=2*x2-7*x+17
- 5*x-3+2*x-2*x2=2*x2-7*x+17
- 5*x-(3+2*x-2*x²)=2*x²-7*x+17
- 5*x-(3+2*x-2*x to the power of 2)=2*x to the power of 2-7*x+17
- 5x-(3+2x-2x^2)=2x^2-7x+17
- 5x-(3+2x-2x2)=2x2-7x+17
- 5x-3+2x-2x2=2x2-7x+17
- 5x-3+2x-2x^2=2x^2-7x+17
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Similar expressions
- 5*x-(3-2*x-2*x^2)=2*x^2-7*x+17
- 5*x-(3+2*x+2*x^2)=2*x^2-7*x+17
- 5*x+(3+2*x-2*x^2)=2*x^2-7*x+17
- 5*x-(3+2*x-2*x^2)=2*x^2-7*x-17
- 5*x-(3+2*x-2*x^2)=2*x^2+7*x+17
5*x-(3+2*x-2*x^2)=2*x^2-7*x+17 equation
The teacher will be very surprised to see your correct solution 😉
The solution
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2 2 5*x + -3 - 2*x + 2*x = 2*x - 7*x + 17
$$5 x + \left(2 x^{2} + \left(- 2 x - 3\right)\right) = \left(2 x^{2} - 7 x\right) + 17$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$2 x^{2} + 3 x = 2 x^{2} - 7 x + 20$$
Move the summands with the unknown x
from the right part to the left part:
$$2 x^{2} + 10 x = 2 x^{2} + 20$$
Divide both parts of the equation by (2*x^2 + 10*x)/x
We get the answer: x = 2
5*x-(3+2*x-2*x^2) = 2*x^2-7*x+17
Expand brackets in the left part
5*x-3-2*x+2*x-2 = 2*x^2-7*x+17
Looking for similar summands in the left part:
-3 + 2*x^2 + 3*x = 2*x^2-7*x+17
Move free summands (without x)
from left part to right part, we given:
$$2 x^{2} + 3 x = 2 x^{2} - 7 x + 20$$
Move the summands with the unknown x
from the right part to the left part:
$$2 x^{2} + 10 x = 2 x^{2} + 20$$
Divide both parts of the equation by (2*x^2 + 10*x)/x
x = 20 + 2*x^2 / ((2*x^2 + 10*x)/x)
We get the answer: x = 2