Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation 25*x^2=16
- Equation 3*x^2-48=0
-
Equation x^2-5*x+7=0
-
Equation x^2-10=0
- Express {x} in terms of y where:
- 1*x+11*y=-3
- -20*x+14*y=16
- 15*x-3*y=19
- 19*x+2*y=17
- Graphing y =:
- 5*x-3*(4*x-1)
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Identical expressions
- five *x- three *(four *x- one)= seven - two *(seven *x+ two)
- 5 multiply by x minus 3 multiply by (4 multiply by x minus 1) equally 7 minus 2 multiply by (7 multiply by x plus 2)
- five multiply by x minus three multiply by (four multiply by x minus one) equally seven minus two multiply by (seven multiply by x plus two)
- 5x-3(4x-1)=7-2(7x+2)
- 5x-34x-1=7-27x+2
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Similar expressions
- 5*x-3*(4*x-1)=7+2*(7*x+2)
- 5*x-3*(4*x+1)=7-2*(7*x+2)
- 5*x-3*(4*x-1)=7-2*(7*x-2)
- 5*x+3*(4*x-1)=7-2*(7*x+2)
5*x-3*(4*x-1)=7-2*(7*x+2) equation
The teacher will be very surprised to see your correct solution 😉
The solution
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5*x - 3*(4*x - 1) = 7 - 2*(7*x + 2)
$$5 x - 3 \left(4 x - 1\right) = 7 - 2 \left(7 x + 2\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$- 7 x = - 14 x$$
Move the summands with the unknown x
from the right part to the left part:
$$7 x = 0$$
Divide both parts of the equation by 7
We get the answer: x = 0
5*x-3*(4*x-1) = 7-2*(7*x+2)
Expand brackets in the left part
5*x-3*4*x+3*1 = 7-2*(7*x+2)
Expand brackets in the right part
5*x-3*4*x+3*1 = 7-2*7*x-2*2
Looking for similar summands in the left part:
3 - 7*x = 7-2*7*x-2*2
Looking for similar summands in the right part:
3 - 7*x = 3 - 14*x
Move free summands (without x)
from left part to right part, we given:
$$- 7 x = - 14 x$$
Move the summands with the unknown x
from the right part to the left part:
$$7 x = 0$$
Divide both parts of the equation by 7
x = 0 / (7)
We get the answer: x = 0
The graph