(5-x)^2-x*((5/2)+x)=0 equation
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The solution
Detail solution
Given the equation:
(5-x)^2-x*((5/2)+x) = 0
Expand expressions:
25 + x^2 - 10*x - x*(5/2 + x) = 0
25 + x^2 - 10*x - x^2 - 5*x/2 = 0
Reducing, you get:
25 - 25*x/2 = 0
Move free summands (without x)
from left part to right part, we given:
$$- \frac{25 x}{2} = -25$$
Divide both parts of the equation by -25/2
x = -25 / (-25/2)
We get the answer: x = 2
Sum and product of roots
[src]
$$2$$
$$2$$
$$2$$
$$2$$