Mister Exam
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How to use it?
- Equation:
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Equation 13/(x+6)=2
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Equation 9x-4x+39=94
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Equation (2-c)+3*(c-3)=-13
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Equation -1+2*x=10*x+3
- Express {x} in terms of y where:
- 14*x+5*y=11
- 3*x-11*y=-7
- 8*x-7*y=-1
- 20*x-5*y=-7
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Identical expressions
- five , eight - one ,6x= zero ,3x- one , eight
- 5,8 minus 1,6x equally 0,3x minus 1,8
- five , eight minus one ,6x equally zero ,3x minus one , eight
- 5,8-1,6x=O,3x-1,8
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Similar expressions
- 5,8+1,6x=0,3x-1,8
- 5,8-1,6x=0,3x+1,8
5,8-1,6x=0,3x-1,8 equation
The teacher will be very surprised to see your correct solution 😉
The solution
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29 8*x 3*x 9 -- - --- = --- - - 5 5 10 5
$$\frac{29}{5} - \frac{8 x}{5} = \frac{3 x}{10} - \frac{9}{5}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$- \frac{8 x}{5} = \frac{3 x}{10} - \frac{38}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-19\right) x}{10} = - \frac{38}{5}$$
Divide both parts of the equation by -19/10
We get the answer: x = 4
(29/5)-(8/5)*x = (3/10)*x-(9/5)
Expand brackets in the left part
29/5-8/5x = (3/10)*x-(9/5)
Expand brackets in the right part
29/5-8/5x = 3/10x-9/5
Move free summands (without x)
from left part to right part, we given:
$$- \frac{8 x}{5} = \frac{3 x}{10} - \frac{38}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-19\right) x}{10} = - \frac{38}{5}$$
Divide both parts of the equation by -19/10
x = -38/5 / (-19/10)
We get the answer: x = 4
The graph