Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 9-8*x=-9*x+15
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Equation 4^x-1/2-6*2^x-1+3=0
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Equation x^2-25=0
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Equation x^2+6*x+7=0
- Express {x} in terms of y where:
- -16*x-9*y=-1
- -15*x+7*y=1
- 18*x-6*y=7
- -19*x+16*y=-9
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Identical expressions
- (fifteen - two x^ two -4x)-(7x-2x^2)= zero
- (15 minus 2x squared minus 4x) minus (7x minus 2x squared ) equally 0
- (fifteen minus two x to the power of two minus 4x) minus (7x minus 2x squared ) equally zero
- (15-2x2-4x)-(7x-2x2)=0
- 15-2x2-4x-7x-2x2=0
- (15-2x²-4x)-(7x-2x²)=0
- (15-2x to the power of 2-4x)-(7x-2x to the power of 2)=0
- 15-2x^2-4x-7x-2x^2=0
- (15-2x^2-4x)-(7x-2x^2)=O
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Similar expressions
- (15+2x^2-4x)-(7x-2x^2)=0
- (15-2x^2-4x)+(7x-2x^2)=0
- (15-2x^2+4x)-(7x-2x^2)=0
- (15-2x^2-4x)-(7x+2x^2)=0
(15-2x^2-4x)-(7x-2x^2)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
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[src]
2 2 15 - 2*x - 4*x + -7*x + 2*x = 0
$$\left(- 4 x + \left(15 - 2 x^{2}\right)\right) + \left(2 x^{2} - 7 x\right) = 0$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 11 x = -15$$
Divide both parts of the equation by -11
We get the answer: x = 15/11
(15-2*x^2-4*x)-(7*x-2*x^2) = 0
Expand brackets in the left part
15-2*x+2-4*x-7*x+2*x-2 = 0
Looking for similar summands in the left part:
15 - 11*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 11 x = -15$$
Divide both parts of the equation by -11
x = -15 / (-11)
We get the answer: x = 15/11
Sum and product of roots
[src]
sum
15 -- 11
$$\frac{15}{11}$$
=
15 -- 11
$$\frac{15}{11}$$
product
15 -- 11
$$\frac{15}{11}$$
=
15 -- 11
$$\frac{15}{11}$$
15/11