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- Equation:
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Equation 0,6-1,6(x-4)=3(7-0,4x)
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Equation 4^(x-1/2)-6*2^(x-1)+3=0
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Equation x^3+3x^2-4x-12=0
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Equation sin(x+1)=0
- Express {x} in terms of y where:
- sqrt(1-x)^2+(4-y)^2=0
- lnx+sin(y/x+2x)=4
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Identical expressions
- eight , seventy-five :3¾=x: zero , seventy-five
- 8,75:3¾ equally x:0,75
- eight , seventy minus five :3¾ equally x: zero , seventy minus five
8,75:3¾=x:0,75 equation
The teacher will be very surprised to see your correct solution 😉
The solution
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[src]
35 ---*3 4*3 x ----- = --- 4 3/4
$$\frac{3 \frac{35}{3 \cdot 4}}{4} = \frac{x}{\frac{3}{4}}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$0 = \frac{4 x}{3} - \frac{35}{16}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-4\right) x}{3} = - \frac{35}{16}$$
Divide both parts of the equation by -4/3
We get the answer: x = 105/64
(35/4)/3*(3/4) = x/(3/4)
Expand brackets in the left part
35/4/33/4 = x/(3/4)
Expand brackets in the right part
35/4/33/4 = x/3/4
Move free summands (without x)
from left part to right part, we given:
$$0 = \frac{4 x}{3} - \frac{35}{16}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-4\right) x}{3} = - \frac{35}{16}$$
Divide both parts of the equation by -4/3
x = -35/16 / (-4/3)
We get the answer: x = 105/64
Sum and product of roots
[src]
sum
105 --- 64
$$\frac{105}{64}$$
=
105 --- 64
$$\frac{105}{64}$$
product
105 --- 64
$$\frac{105}{64}$$
=
105 --- 64
$$\frac{105}{64}$$
105/64