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8-5x=2(x+2)+(4x+2)*2

8-5x=2(x+2)+(4x+2)*2 equation

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Numerical solution:

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The solution

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8 - 5*x = 2*(x + 2) + (4*x + 2)*2
$$8 - 5 x = 2 \left(x + 2\right) + 2 \left(4 x + 2\right)$$
Detail solution
Given the linear equation:
8-5*x = 2*(x+2)+(4*x+2)*2

Expand brackets in the right part
8-5*x = 2*x+2*2+4*x*2+2*2

Looking for similar summands in the right part:
8 - 5*x = 8 + 10*x

Move free summands (without x)
from left part to right part, we given:
$$- 5 x = 10 x$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-15\right) x = 0$$
Divide both parts of the equation by -15
x = 0 / (-15)

We get the answer: x = 0
The graph
Rapid solution [src]
x1 = 0
$$x_{1} = 0$$
x1 = 0
Sum and product of roots [src]
sum
0
$$0$$
=
0
$$0$$
product
0
$$0$$
=
0
$$0$$
0
Numerical answer [src]
x1 = 0.0
x1 = 0.0
The graph
8-5x=2(x+2)+(4x+2)*2 equation