Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation x^2-8*x+17=0
-
Equation 8*x-3*(2*x+1)=2*x+4
-
Equation -x/12+x=55/12
-
Equation 3*9^(x-1/2)-7*6^x+3*4^(x+1)=0
- Express {x} in terms of y where:
- 7*x+19*y=12
- 12*x-14*y=20
- -20*x-14*y=5
- -18*x+8*y=-2
- Sum of series:
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10
- Derivative of:
-
10
- Integral of d{x}:
-
10
-
Identical expressions
- Ctgx= ten
- Ctgx equally 10
- Ctgx equally ten
-
Similar expressions
- Ctg(x)=7
Ctgx=10 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$\cot{\left(x \right)} = 10$$
transform
$$\cot{\left(x \right)} - 10 = 0$$
$$\cot{\left(x \right)} - 10 = 0$$
Do replacement
$$w = \cot{\left(x \right)}$$
Move free summands (without w)
from left part to right part, we given:
$$w = 10$$
We get the answer: w = 10
do backward replacement
$$\cot{\left(x \right)} = w$$
substitute w:
$$\cot{\left(x \right)} = 10$$
transform
$$\cot{\left(x \right)} - 10 = 0$$
$$\cot{\left(x \right)} - 10 = 0$$
Do replacement
$$w = \cot{\left(x \right)}$$
Move free summands (without w)
from left part to right part, we given:
$$w = 10$$
We get the answer: w = 10
do backward replacement
$$\cot{\left(x \right)} = w$$
substitute w:
Sum and product of roots
[src]
sum
acot(10)
$$\operatorname{acot}{\left(10 \right)}$$
=
acot(10)
$$\operatorname{acot}{\left(10 \right)}$$
product
acot(10)
$$\operatorname{acot}{\left(10 \right)}$$
=
acot(10)
$$\operatorname{acot}{\left(10 \right)}$$
acot(10)