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(Abs((|x|)+1))=4 equation

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Numerical solution:

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The solution

You have entered [src]
||x| + 1| = 4
$$\left|{\left|{x}\right| + 1}\right| = 4$$
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.

1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$x - 3 = 0$$
after simplifying we get
$$x - 3 = 0$$
the solution in this interval:
$$x_{1} = 3$$

2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$- x - 3 = 0$$
after simplifying we get
$$- x - 3 = 0$$
the solution in this interval:
$$x_{2} = -3$$


The final answer:
$$x_{1} = 3$$
$$x_{2} = -3$$
The graph
Rapid solution [src]
x1 = -3
$$x_{1} = -3$$
x2 = 3
$$x_{2} = 3$$
x2 = 3
Sum and product of roots [src]
sum
-3 + 3
$$-3 + 3$$
=
0
$$0$$
product
-3*3
$$- 9$$
=
-9
$$-9$$
-9
Numerical answer [src]
x1 = -3.0
x2 = 3.0
x2 = 3.0