Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2*sin(x)=0
-
Equation (x-5)^2-x^2=3
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Equation -2*(-y-2)-y-2=0
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Equation x^2+x=6
- Express {x} in terms of y where:
- -6*x+15*y=-13
- -17*x+14*y=11
- -11*x-3*y=-15
- 9*x-6*y=-20
- Integral of d{x}:
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2x
- Derivative of:
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2x
- Graphing y =:
- 2x
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Identical expressions
- 8x(one +2x)-(4x+ three)(4x- three)=2x
- 8x(1 plus 2x) minus (4x plus 3)(4x minus 3) equally 2x
- 8x(one plus 2x) minus (4x plus three)(4x minus three) equally 2x
- 8x1+2x-4x+34x-3=2x
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Similar expressions
- 8x(1+2x)-(4x-3)(4x-3)=2x
- 2*x^2-8*x+11=0
- 2^x=-4
- 8x(1+2x)-(4x+3)(4x+3)=2x
- 8x(1-2x)-(4x+3)(4x-3)=2x
- 8x(1+2x)+(4x+3)(4x-3)=2x
8x(1+2x)-(4x+3)(4x-3)=2x equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
8*x*(1 + 2*x) - (4*x + 3)*(4*x - 3) = 2*x
$$8 x \left(2 x + 1\right) - \left(4 x - 3\right) \left(4 x + 3\right) = 2 x$$
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$6 x = -9$$
Divide both parts of the equation by 6
We get the answer: x = -3/2
8*x*(1+2*x)-(4*x+3)*(4*x-3) = 2*x
Expand expressions:
8*x + 16*x^2 - (4*x + 3)*(4*x - 3) = 2*x
8*x + 16*x^2 + 9 - 16*x^2 = 2*x
Reducing, you get:
9 + 6*x = 0
Move free summands (without x)
from left part to right part, we given:
$$6 x = -9$$
Divide both parts of the equation by 6
x = -9 / (6)
We get the answer: x = -3/2
Sum and product of roots
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sum
-3/2
$$- \frac{3}{2}$$
=
-3/2
$$- \frac{3}{2}$$
product
-3/2
$$- \frac{3}{2}$$
=
-3/2
$$- \frac{3}{2}$$
-3/2
The graph