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How to use it?
- Equation:
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Equation 12-(4-x)^2=x(3-x)
-
Equation (x+6)^2=(15-x)^2
-
Equation 4x(x-1)-8=(1+2x)(2x-1)-6x
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Equation -3x+9=0
- Express {x} in terms of y where:
- -11*x+3*y=5
- 9*x-17*y=-12
- 18*x-16*y=-11
- -11*x-14*y=6
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Identical expressions
- 7x+ thirteen =-5x- twenty-five
- 7x plus 13 equally minus 5x minus 25
- 7x plus thirteen equally minus 5x minus twenty minus five
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Similar expressions
- 7x+13=+5x-25
- 7x-13=-5x-25
- 7x+13=-5x+25
- (7*x+1)*(3*x-1)-21^2=3
- (7x+1)^3=49x^2(7x+3)+2(10x+3)
7x+13=-5x-25 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$7 x = - 5 x - 38$$
Move the summands with the unknown x
from the right part to the left part:
$$12 x = -38$$
Divide both parts of the equation by 12
We get the answer: x = -19/6
7*x+13 = -5*x-25
Move free summands (without x)
from left part to right part, we given:
$$7 x = - 5 x - 38$$
Move the summands with the unknown x
from the right part to the left part:
$$12 x = -38$$
Divide both parts of the equation by 12
x = -38 / (12)
We get the answer: x = -19/6
Sum and product of roots
[src]
sum
-19/6
$$- \frac{19}{6}$$
=
-19/6
$$- \frac{19}{6}$$
product
-19/6
$$- \frac{19}{6}$$
=
-19/6
$$- \frac{19}{6}$$
-19/6