Mister Exam
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How to use it?
- Equation:
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Equation -2*x^3/(x^2-1)^2+2*x/(x^2-1)=0
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Equation (x^2-16)/(x+4)=0
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Equation x^6=-3
- Equation 50018-а=44
- Express {x} in terms of y where:
- -5*x+5*y=-15
- -15*x-4*y=7
- -18*x+5*y=11
- -3*x+3*y=17
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Identical expressions
- 6x+ twenty-three = eight - seventeen
- 6x plus 23 equally 8 minus 17
- 6x plus twenty minus three equally eight minus seventeen
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Similar expressions
- (1+T_2-3∙10∙T_2)[1+1719∙T_2-2∙(1+T_2)∙10+3T_2∙10^2]=T_2[343.8-(1719∙T_2+1)∙10+(1+T_2)∙10^2-T_2∙10^3]
- 3*x-4=6*x+23
- 6x-23=8-17
- 6x+23=8+17
6x+23=8-17 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$6 x = -32$$
Divide both parts of the equation by 6
We get the answer: x = -16/3
6*x+23 = 8-17
Looking for similar summands in the right part:
23 + 6*x = -9
Move free summands (without x)
from left part to right part, we given:
$$6 x = -32$$
Divide both parts of the equation by 6
x = -32 / (6)
We get the answer: x = -16/3
Sum and product of roots
[src]
sum
-16/3
$$- \frac{16}{3}$$
=
-16/3
$$- \frac{16}{3}$$
product
-16/3
$$- \frac{16}{3}$$
=
-16/3
$$- \frac{16}{3}$$
-16/3