(6x+1)-(3-2*x)=14 equation
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The solution
Detail solution
Given the linear equation:
(6*x+1)-(3-2*x) = 14
Expand brackets in the left part
6*x+1-3+2*x = 14
Looking for similar summands in the left part:
-2 + 8*x = 14
Move free summands (without x)
from left part to right part, we given:
$$8 x = 16$$
Divide both parts of the equation by 8
x = 16 / (8)
We get the answer: x = 2
Sum and product of roots
[src]
$$2$$
$$2$$
$$2$$
$$2$$