6a+(3a-2)=14 equation
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The solution
Detail solution
Given the linear equation:
6*a+(3*a-2) = 14
Expand brackets in the left part
6*a+3*a-2 = 14
Looking for similar summands in the left part:
-2 + 9*a = 14
Move free summands (without a)
from left part to right part, we given:
$$9 a = 16$$
Divide both parts of the equation by 9
a = 16 / (9)
We get the answer: a = 16/9
Sum and product of roots
[src]
$$\frac{16}{9}$$
$$\frac{16}{9}$$
$$\frac{16}{9}$$
$$\frac{16}{9}$$