Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 3*x^2-9=0
- Equation x^4-35*x^2-36=0
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Equation x^3=64
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Equation x/(x^2-1)=0
- Express {x} in terms of y where:
- 7*x-2*y=18
- 1*x+6*y=6
- -16*x-12*y=12
- -17*x-12*y=-9
- Graphing y =:
- 5x+4
- x-12
- Derivative of:
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5x+4
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Identical expressions
- 5x+ four =x- twelve
- 5x plus 4 equally x minus 12
- 5x plus four equally x minus twelve
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Similar expressions
- 25^x+4×5^x–5=0
- 5x+4=x+12
- x^2+5*x+4=0
- (1/(x*(x-1)*(x-4)*(x-3)*(x-2)))*(((5*(x-5))*(x-6))*(x-7)+(x-8)*((5*(x-5))*(x-6)+(x-7)*(-30+5*x+5*(x-5))))+5*(x-8)*(x-7)*(x-6)*(x-5)*(-(x*(x-1))*(x-2)*(x-3)-(x-4)*((x*(x-1))*(x-2)+(x-3)*(x*(x-1)+(-1+2*x)*(x-2))))/(x^2*(x-1)^2*(x-4)^2*(x-3)^2*(x-2)^2)=0
- 5x-4=x-12
5x+4=x-12 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$5 x = x - 16$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = -16$$
Divide both parts of the equation by 4
We get the answer: x = -4
5*x+4 = x-12
Move free summands (without x)
from left part to right part, we given:
$$5 x = x - 16$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = -16$$
Divide both parts of the equation by 4
x = -16 / (4)
We get the answer: x = -4