Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 9^x-8*3^x-9=0
- Equation x+y=4
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Equation 5x+8=-12
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Equation x/9+x=-3
- Express {x} in terms of y where:
- 18*x+17*y=-14
- 16*x-17*y=-15
- -4*x-4*y=19
- 15*x+1*y=19
- Derivative of:
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6x
- Integral of d{x}:
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6x
- Canonical form:
- 6x
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Identical expressions
- 5x- two *(x- four)=6x
- 5x minus 2 multiply by (x minus 4) equally 6x
- 5x minus two multiply by (x minus four) equally 6x
- 5x-2(x-4)=6x
- 5x-2x-4=6x
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Similar expressions
- 0,6(x-2)+4,6=0,4(7+x)
- 5x+2*(x-4)=6x
- (x^2-6*x-16)*sqrt(x-3)=0
- 6*x=12
- 5x-2*(x+4)=6x
- 5-2(x-7)=5x-(2x-4)
5x-2*(x-4)=6x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$3 x = 6 x - 8$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-3\right) x = -8$$
Divide both parts of the equation by -3
We get the answer: x = 8/3
5*x-2*(x-4) = 6*x
Expand brackets in the left part
5*x-2*x+2*4 = 6*x
Looking for similar summands in the left part:
8 + 3*x = 6*x
Move free summands (without x)
from left part to right part, we given:
$$3 x = 6 x - 8$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-3\right) x = -8$$
Divide both parts of the equation by -3
x = -8 / (-3)
We get the answer: x = 8/3
Sum and product of roots
[src]
sum
8/3
$$\frac{8}{3}$$
=
8/3
$$\frac{8}{3}$$
product
8/3
$$\frac{8}{3}$$
=
8/3
$$\frac{8}{3}$$
8/3