Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation sinx=1
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Equation cosx=1/2
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Equation sqrt(x)+1=x-1
- Equation (7*z^3-3*z-4)=0
- Express {x} in terms of y where:
- 12*10^(-30)-0,1884*10^12*x^2-y(0,3768*10^12*x+1,183152*10^12*x^3)+y^2(2,760688*10^24*x^2)=0=0
- (x^2+y^2)×(x+y-3)=2xy
- sqrt(1-x)^2+(4-y)^2=0
- lnx+sin(y/x+2x)=4
- Integral of d{x}:
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(5x+2)
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Identical expressions
- (5x- one) two =(5x+ two)
- (5x minus 1)2 equally (5x plus 2)
- (5x minus one) two equally (5x plus two)
- 5x-12=5x+2
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Similar expressions
- 5x-12=4x-8
- 3-(1,5x-12,8)=45,8-4x
- 25^x-20×5^x-125=0
- (5x+1)2=(5x+2)
- -45*x-12*x=90
- 8x+3=5x+29
- 22:(9x-1,8)-11:(5x+2,5)=0
- *x^2+15*x+2*sqrt(x^2+5*x+1)=2
- (5x-1)2=(5x-2)
(5x-1)2=(5x+2) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$10 x = 5 x + 4$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = 4$$
Divide both parts of the equation by 5
We get the answer: x = 4/5
(5*x-1)*2 = (5*x+2)
Expand brackets in the left part
5*x*2-1*2 = (5*x+2)
Expand brackets in the right part
5*x*2-1*2 = 5*x+2
Move free summands (without x)
from left part to right part, we given:
$$10 x = 5 x + 4$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = 4$$
Divide both parts of the equation by 5
x = 4 / (5)
We get the answer: x = 4/5
Sum and product of roots
[src]
sum
4/5
$$\frac{4}{5}$$
=
4/5
$$\frac{4}{5}$$
product
4/5
$$\frac{4}{5}$$
=
4/5
$$\frac{4}{5}$$
4/5