Mister Exam
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How to use it?
- Equation:
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Equation x^3+4*x^2-x-4=0
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Equation (x+2)^4+(x+2)^2-12=0
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Equation 2*cos(x)+1=0
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Equation 8x-8=20-6x
- Express {x} in terms of y where:
- -19*x+1*y=0
- -8*x-15*y=15
- 14*x-13*y=-10
- 1*x-6*y=-19
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Identical expressions
- 4x- three (twenty -x)=10x- three (eleven +x)
- 4x minus 3(20 minus x) equally 10x minus 3(11 plus x)
- 4x minus three (twenty minus x) equally 10x minus three (eleven plus x)
- 4x-320-x=10x-311+x
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Similar expressions
- 4x-3(20-x)=10x-3(11-x)
- 4x-3(20-x)=10x+3(11+x)
- 4x+3(20-x)=10x-3(11+x)
- 4x-3(20+x)=10x-3(11+x)
4x-3(20-x)=10x-3(11+x) equation
The teacher will be very surprised to see your correct solution 😉
The solution
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4*x - 3*(20 - x) = 10*x - 3*(11 + x)
$$4 x - 3 \left(20 - x\right) = 10 x - 3 \left(x + 11\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$7 x = 7 x + 27$$
Move the summands with the unknown x
from the right part to the left part:
$$0 = 27$$
This equation has no roots
4*x-3*(20-x) = 10*x-3*(11+x)
Expand brackets in the left part
4*x-3*20+3*x = 10*x-3*(11+x)
Expand brackets in the right part
4*x-3*20+3*x = 10*x-3*11-3*x
Looking for similar summands in the left part:
-60 + 7*x = 10*x-3*11-3*x
Looking for similar summands in the right part:
-60 + 7*x = -33 + 7*x
Move free summands (without x)
from left part to right part, we given:
$$7 x = 7 x + 27$$
Move the summands with the unknown x
from the right part to the left part:
$$0 = 27$$
This equation has no roots
The graph