3y-2(2+y)=3y-5 equation
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The solution
Detail solution
Given the linear equation:
3*y-2*(2+y) = 3*y-5
Expand brackets in the left part
3*y-2*2-2*y = 3*y-5
Looking for similar summands in the left part:
-4 + y = 3*y-5
Move free summands (without y)
from left part to right part, we given:
$$y = 3 y - 1$$
Move the summands with the unknown y
from the right part to the left part:
$$\left(-2\right) y = -1$$
Divide both parts of the equation by -2
y = -1 / (-2)
We get the answer: y = 1/2
Sum and product of roots
[src]
$$\frac{1}{2}$$
$$\frac{1}{2}$$
$$\frac{1}{2}$$
$$\frac{1}{2}$$