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3y-2(2+y)=3y-5 equation

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Numerical solution:

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The solution

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3*y - 2*(2 + y) = 3*y - 5
$$3 y - 2 \left(y + 2\right) = 3 y - 5$$
Detail solution
Given the linear equation:
3*y-2*(2+y) = 3*y-5

Expand brackets in the left part
3*y-2*2-2*y = 3*y-5

Looking for similar summands in the left part:
-4 + y = 3*y-5

Move free summands (without y)
from left part to right part, we given:
$$y = 3 y - 1$$
Move the summands with the unknown y
from the right part to the left part:
$$\left(-2\right) y = -1$$
Divide both parts of the equation by -2
y = -1 / (-2)

We get the answer: y = 1/2
The graph
Rapid solution [src]
y1 = 1/2
$$y_{1} = \frac{1}{2}$$
y1 = 1/2
Sum and product of roots [src]
sum
1/2
$$\frac{1}{2}$$
=
1/2
$$\frac{1}{2}$$
product
1/2
$$\frac{1}{2}$$
=
1/2
$$\frac{1}{2}$$
1/2
Numerical answer [src]
y1 = 0.5
y1 = 0.5