Mister Exam
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How to use it?
- Equation:
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Equation x^3=x^2+2x
- Equation x^3+6x^2-x-6=0
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Equation (x-1)*(x^2+8*x+16)=6*(x+4)
- Equation x^3+2*x^2-36*x-72=0
- Express {x} in terms of y where:
- 12*x+10*y=17
- 14*x+7*y=-4
- -15*x-16*y=12
- 16*x+9*y=-18
- Integral of d{x}:
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3x+4
- Canonical form:
- 3x+4
- Sum of series:
- 3x+4
- Limit of the function:
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-19
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Identical expressions
- 3x+ four =- nineteen
- 3x plus 4 equally minus 19
- 3x plus four equally minus nineteen
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Similar expressions
- 3x+4=+19
- 3*x+4*3*x+1=13
- |x+3|+|x-5|=3*x+4
- (x+5)(3-x)+(x-3)(x+4)=8
- 13*y^2-14/sqrt(13)*y-8/sqrt(13)*x+4=0
- 3x-4=-19
3x+4=-19 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$3 x = -23$$
Divide both parts of the equation by 3
We get the answer: x = -23/3
3*x+4 = -19
Move free summands (without x)
from left part to right part, we given:
$$3 x = -23$$
Divide both parts of the equation by 3
x = -23 / (3)
We get the answer: x = -23/3
Sum and product of roots
[src]
sum
-23/3
$$- \frac{23}{3}$$
=
-23/3
$$- \frac{23}{3}$$
product
-23/3
$$- \frac{23}{3}$$
=
-23/3
$$- \frac{23}{3}$$
-23/3