Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation (x^2+3)/(x^2+1)=2
-
Equation 4x^3-4x=0
-
Equation x-4/3+x/2=5
-
Equation -x=3,5
- Express {x} in terms of y where:
- 8*x+11*y=-10
- -6*x-12*y=-17
- -14*x+20*y=-17
- 3*x-7*y=-20
-
Identical expressions
- 3x- five + four (five -7x)- two (six -8x)= zero
- 3x minus 5 plus 4(5 minus 7x) minus 2(6 minus 8x) equally 0
- 3x minus five plus four (five minus 7x) minus two (six minus 8x) equally zero
- 3x-5+45-7x-26-8x=0
- 3x-5+4(5-7x)-2(6-8x)=O
-
Similar expressions
- 3x-5+4(5-7x)-2(6+8x)=0
- 3*x-5+4*(5-7*x)-2*(6-8*x)=0
- 3x-5+4(5-7x)+2(6-8x)=0
- 3x+5+4(5-7x)-2(6-8x)=0
- 3x-5-4(5-7x)-2(6-8x)=0
- 3x-5+4(5+7x)-2(6-8x)=0
3x-5+4(5-7x)-2(6-8x)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
3*x - 5 + 4*(5 - 7*x) - 2*(6 - 8*x) = 0
$$- 2 \left(6 - 8 x\right) + \left(4 \left(5 - 7 x\right) + \left(3 x - 5\right)\right) = 0$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 9 x = -3$$
Divide both parts of the equation by -9
We get the answer: x = 1/3
3*x-5+4*(5-7*x)-2*(6-8*x) = 0
Expand brackets in the left part
3*x-5+4*5-4*7*x-2*6+2*8*x = 0
Looking for similar summands in the left part:
3 - 9*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 9 x = -3$$
Divide both parts of the equation by -9
x = -3 / (-9)
We get the answer: x = 1/3
Sum and product of roots
[src]
sum
1/3
$$\frac{1}{3}$$
=
1/3
$$\frac{1}{3}$$
product
1/3
$$\frac{1}{3}$$
=
1/3
$$\frac{1}{3}$$
1/3