Mister Exam
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How to use it?
- Equation:
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Equation 9-8*x=-9*x+15
-
Equation 4^x-1/2-6*2^x-1+3=0
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Equation x^2-25=0
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Equation x^2+6*x+7=0
- Express {x} in terms of y where:
- -16*x-9*y=-1
- -15*x+7*y=1
- 18*x-6*y=7
- -19*x+16*y=-9
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Identical expressions
- 3x-5x- two / two -x= zero
- 3x minus 5x minus 2 divide by 2 minus x equally 0
- 3x minus 5x minus two divide by two minus x equally zero
- 3x-5x-2/2-x=O
- 3x-5x-2 divide by 2-x=0
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Similar expressions
- 3x-5x-2/2+x=0
- 3x-5x+2/2-x=0
- 3x+5x-2/2-x=0
3x-5x-2/2-x=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
3*x - 5*x - 1 - x = 0
$$- x + \left(\left(- 5 x + 3 x\right) - 1\right) = 0$$
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 3 x = 1$$
Divide both parts of the equation by -3
We get the answer: x = -1/3
3*x-5*x-2/2-x = 0
Looking for similar summands in the left part:
-1 - 3*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 3 x = 1$$
Divide both parts of the equation by -3
x = 1 / (-3)
We get the answer: x = -1/3
Sum and product of roots
[src]
sum
-1/3
$$- \frac{1}{3}$$
=
-1/3
$$- \frac{1}{3}$$
product
-1/3
$$- \frac{1}{3}$$
=
-1/3
$$- \frac{1}{3}$$
-1/3