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3log16((x^2+1)^2+x)+log2((x^2+1)^2-x)=log16(4x+1)-0,5 equation

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     /        2    \      /        2    \                   
     |/ 2    \     |      |/ 2    \     |                   
  log\\x  + 1/  + x/   log\\x  + 1/  - x/   log(4*x + 1)   1
3*------------------ + ------------------ = ------------ - -
       log(16)               log(2)           log(16)      2
$$\frac{\log{\left(- x + \left(x^{2} + 1\right)^{2} \right)}}{\log{\left(2 \right)}} + 3 \frac{\log{\left(x + \left(x^{2} + 1\right)^{2} \right)}}{\log{\left(16 \right)}} = \frac{\log{\left(4 x + 1 \right)}}{\log{\left(16 \right)}} - \frac{1}{2}$$